浅析int*p[ ]与int(*p)[ ]的区别

<SPAN style="BACKGROUND-COLOR: rgb(255,255,255)">#include <iostream>
using namespace std;
int main(int argc, char* argv[])
 {
int* p[2];
int a[3] = {1, 2, 3};
int b[4] = {4, 5, 6, 7};
p[0] = a;
p[1] = b;
for(int i = 0; i < 3; i++)
cout << *p[0] + i;// cout << **p + i;
cout << endl;
for(i = 0; i < 4; i++)
cout << *p[1] + i;// cout << **p + i;
return 0;
}</SPAN>

<SPAN style="BACKGROUND-COLOR: rgb(255,255,255)">#include <iostream>
using namespace std;
void main() {
int (*p)[2];
int b[3][2] = {{1, 2}, {3, 4}, {5, 6}};
p = b;
for(int i = 0; i < 3; i++) {
for(int j = 0; j < 2; j++) //cout << p[i][j]; //cout << *(*(p+i)+j);
cout << endl;
}
}</SPAN>

<SPAN style="BACKGROUND-COLOR: rgb(255,255,255)">#include <iostream>
using namespace std;
void main() {
int** array;
array = new int* [2];
int a[3] = {1, 2, 3};
int b[4] = {4, 5, 6, 7};
array[0] = a; // *array = a;
array[1] = b; // *(array+1) = b;
for(int i = 0; i < 3; i++) cout << array[0][i];// cout << *array[0] + i;
cout << endl;
for(int j = 0; j < 4; j++) cout << array[1][j];// cout << *array[1] + j;
}</SPAN>