C#使用windows服务开启应用程序的方法

//该函数是为了windows服务和桌面交互
private void serviceInstaller1_AfterInstall(object sender, InstallEventArgs e)
{
 base.OnAfterInstall(e.SavedState);
 ManagementObject wmiService = null;
 ManagementBaseObject InParam = null;
 try
 {
  wmiService = new ManagementObject(string.Format("Win32_Service.Name='{0}'", serviceInstaller1.ServiceName));
  InParam = wmiService.GetMethodParameters("Change");
  InParam["DesktopInteract"] = true;
  wmiService.InvokeMethod("Change", InParam, null);
 }
 finally
 {
  if (InParam != null)
   InParam.Dispose();
  if (wmiService != null)
   wmiService.Dispose();
 }
}